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Topic: Electrical question about 6 volt vs. 12 volt pumps  (Read 1816 times)

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troutnut

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  • Location: Salem, OR. USA (I am a refugee from The People's Socialist Republic of Kalifornia hiding out in Oregon until my homeland returns to sanity)
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I need advice from electrical engineer types out there... I am going to run my bait bucket on 6 volt instead of 12 volt, so I can slow the pump down and make the battery last longer. It is designed to run on 12 volt, 550 gph. My question is regarding the fuse, I have a 3 amp fuse for the 12 volt system, do you change the fuse if you lower the volts and if so, what amp fuse should I put in?


Fish Master1

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Dont change the fuse size.
..........Sincerly A-Hull Muggle.


fishbutt21

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You may want to study up on your OHMS law but I think if you lower the voltage it will pull more amps and run the battery out faster than if its ran at a higher voltage and low amps.and since a battery of any given size only has so many amps stored it will die faster  rather than lasting longer
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polepole

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You may want to study up on your OHMS law but I think if you lower the voltage it will pull more amps and run the battery out faster than if its ran at a higher voltage and low amps.and since a battery of any given size only has so many amps stored it will die faster  rather than lasting longer

The 6V will still run for more than a day or 2, and it does pump less.  I run one (design courtesy of SBD).  It's a 3 or 4 Ah model too if that helps.

-Allen


finaegelin

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Actually for a given device, reducing the applied voltage usually means less amps. Running a working device like a pump at a lower speed also means less work, less power, and probably fewer amps also.

So keep the same fuse and all will remain safely protected.

If the load was a constant power load (there aren't too many of these in the world), the amps would go up as the voltage went down, since power = volts times amps. That's what fishbutt21 was talking about, I think.

Good Luck with your project.


polepole

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Ohm's Law ... V=I*R.  Or I=V/R.  For a fixed R (the load of the pump), if V is lower, then I is lower.

-Allen


SBD

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It works fine.  A 6v will run it for ages...btdt.